How much heat must be removed from a 260 g block of copper to lower its temperature from 150°C to 11°C?

Original Question:





How much heat must be removed from a 260 g block of copper to lower its temperature from 150°C to 11°C? The specific heat capacity of copper is 0.093 cal/g·C°.

How much heat must be removed from a 260 g block of copper to lower its temperature from 150°C to 11°C?
Heat=mass X specific heat X change in temp





Heat = 260g X .093 X (150-11)=3361 calories
Reply:energy = massX(change in temp)X(sp heat capacity)


= 260 X 0.093 X (150-11)


= 3361 cal


Ideally I would like to change this to Joules.
Reply:Do you really need the people of Yahoo! Answers to do your homework for you?





260 g * (150-11)degC * 0.093cal/g*degC = use your calculator [units are calories]
Reply:3361.02 calories





heat in calories = mass x specific heat x change in temp
Reply:Enerjy=mc(11-150)=0/26 * c * -139=...


260g=0/26kg Based on SI(System International)


Every element has a specific "C"